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C Language > Learn C Language > What is the output of the below: int x, y; printf("%d",...
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What is the output of the below: int x, y; printf("%d", scanf("%d %d", &x, &Y));

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:) Good one. It checks my eye sight. This piece of code would result in an error: "undefined symbol Y". Note: 'scanf( )' not only scans and loads the values entered by users into variables, but it also returns a number which is the count of the number of variables that are successfully scanned by...
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:) Good one. It checks my eye sight. This piece of code would result in an error: "undefined symbol Y". Note: 'scanf( )' not only scans and loads the values entered by users into variables, but it also returns a number which is the count of the number of variables that are successfully scanned by itself. So, in this example if the upper case 'Y' in 'scanf( )' is replaced with lower case 'y', the scanf( ) would return 2 on successfully scanning the input values (say 10 and 20) to memory. read less
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Answer will no of variable read by scanf that is "2". and please make sure "Y" is not capital, because C is case sensitive language
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Experienced IT Professional with 5 years of experience in Tutoring Programming subjects

scanf is used for reading inputs from the user. So user will be prompted to enter 2 integer numbers. scanf returns the number of successfully read inputs. suppose I entered 15 20 printf is used to prints the value of the variables or value returned by any function. In our case it will print the...
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scanf is used for reading inputs from the user. So user will be prompted to enter 2 integer numbers. scanf returns the number of successfully read inputs. suppose I entered 15 20 printf is used to prints the value of the variables or value returned by any function. In our case it will print the output or return value of the scanf function which will be 2. So complete output will be: 15 20 2 read less
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Output is 2. why? ans. printf function will count the number of variables that has been scanned because you specify %d which refers to integer.
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It would not compile at the very first. So, there is no scope to run this program. Conclusion is, it would not print anything on the output window.
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It would not compile at very first. So, there is no scope to run this code. Finally, it would not print anything on the output window.
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Hi Pravalika, First thing is you should not ask questions like this (o/p of program etc..), as you can always verify with any compiler you use. You should always ask questions like why such thing..? (Ex. you can ask why the o/p of above program is 5?) Thanks, Janardhan.
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First of all writing such code is not valid but still output concern it is 2, because scanf is library function and it have two parameters
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